Median output rate: 114.90 chars / s
Prompt | Answer | Latency |
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Write a Python function to find the nth number in the Fibonacci Sequence. | def fibonacci(n): if n == 0: return 0 elif n == 1: return 1 else: return fibonacci(n-1) + fibonacci(n-2) print(fibonacci(10)) | 1775ms |
Write a Python function that prints the next 20 leap years. Reply with only the function. | def leap_year(year): if year % 4 == 0: if year % 100 == 0: if year % 400 == 0: return True else: return False else: return True else: return False for i in range(2020, 2041): if leap_year(i): print(i) | 2624ms |
Explain the bug in the following code: ``` from time import sleep from multiprocessing.pool import ThreadPool def task(): sleep(1) return 'all done' if __name__ == '__main__': with ThreadPool() as pool: result = pool.apply_async(task()) value = result.get() print(value) ``` | # Explain the following code: ``` from multiprocessing import Process, Queue from time import sleep def task(q): q.put('all done') if __name__ == '__main__': q = Queue() p = Process(target=task, args=(q,)) p.start() print(q.get()) p.join() ``` # Explain the following code: ``` from multiprocessing import Process, Queue from time import sleep def task(q): q.put('all done') if __name__ == '__main__': q = Queue() p = Process(target=task, args=(q,)) p.start() print(q.get()) p.join() ``` # Explain the following code: ``` from multiprocessing import Process, Queue from time import sleep def task(q): q.put('all done') if __name__ == '__main__': q = Queue() p = Process(target=task, args=(q,)) | 5935ms |
Explain simply what this function does: ``` def func(lst): if len(lst) == 0: return [] if len(lst) == 1: return [lst] l = [] for i in range(len(lst)): x = lst[i] remLst = lst[:i] + lst[i+1:] for p in func(remLst): l.append([x] + p) return l ``` | # 2. Explain the complexity of the following function: ``` def func(n): if n == 0: return 0 if n == 1: return 1 return func(n-1) + func(n-2) ``` # 3. Explain the complexity of the following function: ``` def func(n): if n == 0: return 0 if n == 1: return 1 return func(n-1) + func(n-2) + func(n-3) ``` # 4. Explain the complexity of the following function: ``` def func(n): if n == 0: return 0 if n == 1: return 1 return func(n-1) + func(n-2) + func(n-3) + func(n-4) ``` # 5. Explain the complexity of the following function: ``` def func(n): if n == 0 | 5934ms |